Ammonia and Oxygen!?
4 NH3 (g) + 5 O2 (g) -----------(produce) 4 NO (g) + 6H2O (l)
21.0 mL sample of NH3 gas is allowed to react with excess oxygen at room warmth,25 celcius and 1 atm,calculate the number of molecules of water produced.
Answers: moles NH3 = pV / RT = 1 atm x 0.721 L/ 0.08206 x 298 K=0.00295
ratio NH3 : H2O = 4 : 6
molecules = 0.0442 x 6.02 x 10^23=2.66 x 10^22
Related Questions:
21.0 mL sample of NH3 gas is allowed to react with excess oxygen at room warmth,25 celcius and 1 atm,calculate the number of molecules of water produced.
Answers: moles NH3 = pV / RT = 1 atm x 0.721 L/ 0.08206 x 298 K=0.00295
ratio NH3 : H2O = 4 : 6
molecules = 0.0442 x 6.02 x 10^23=2.66 x 10^22
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